#### a. Traverse with Bearings

Figure E-6 Bearing Traverse Example |

Line |
Bearing |
Length (ft) |
Lat (ft) |
Dep (ft) |

AB | S 68°05'35"W | 472.68 | -176.357 | -438.548 |

BC | N 19°46'00"W | 216.13 | +203.395 | -73.093 |

CD | N 45°55'20"E | 276.52 | +192.357 | +198.651 |

DA | S 54°59'15"E | 382.24 | -219.312 | +313.065 |

sums: |
1347.57 | +0.083 | +0.075 | |

Distance |
Lat errtoo far N |
Dep errtoo far E |

##### (1) Adjust the Lats and Deps

Setup Equations E-1 and E-2:

Now solve Equations E-3 and E-4 for each line:

*Line AB*

*Line BC*

*Line CD*

*Line DA*

*Check the closure condition*

Adjusted |
||

Line |
Lat (ft) |
Dep (ft) |

AB | -176.386 | -438.574 |

BC | +203.382 | -73.105 |

CD | +192.340 | +198.635 |

DE | -219.336 | +313.044 |

sums: |
0.000 | 0.000 |

check |
check |

A common mistake is to forget to negate *Lat err* and *Dep err* in the correction equations. If that happens, the closure condition will be *twice* what it originally was as the corrections were applied in the wrong direction.

##### (2) Compute adjusted lengths and directions

Use Equations E-5 and E-6 along with Figure E-5 to compute the new length and direction for each line.

*Line AB*

Adj Lat = -176.386 <- South

Adj Dep = -438.574 <- West

Because it's the SW quadrant, Brng =S 68°05'27.4" W.

*Line BC*

Adj Lat = +203.382 <- North

Adj Dep = -73.105 <- West

Because it's the NW quadrant, Brng = N 19°46'14.9" W

*Line CD*

Adj Lat = +192.340 <- North

Adj Dep = +198.635 <- East

Because it's the NE quadrant, Brng = N 45°55'20.7" E

*Line DA*

Adj Lat = -219.336 <- South

Adj Dep = +313.044 <- East

Because it's the SE quadrant, Brng = S 54°58'58.0" E

##### (3) Adjustment summary

Adjusted |
Adjusted |
|||

Line |
Lat (ft) |
Dep (ft) |
Length |
Bearing |

AB | -176.386 | -438.574 | 472.715 | S 68°05'27.4" W |

BC | +203.382 | -73.105 | 216.122 | N 19°46'14.9" W |

CD | +192.340 | +198.635 | 276.479 | N 45°55'20.7" E |

DE | -219.336 | +313.044 | 382.237 | S 54°58'58.0" E |