E. Example Intersections
Two different intersection types are solved using triangle- and arc-based methods to demonstrate the different computation process. Additional decimal places will be carried in computations to minimize rounding errors.
1. Distance-distance
Given the information on the diagram, determine the coordinates of point 101.
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Figure E-1 |
Step (1) For both methods is to inverse along the base line 30-20
a. Triangle-based method
Step (2) Compute angle at 30 by Law of Cosines. |
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Step (3) Compute direction from 30 to 101. |
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Step (4) Perform a forward computation from 30 to 101. |
Math Check: Compute coordinates from 20.
Step (1) Compute angle at 20 by Law of Sines. |
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Step (2) Compute direction from 20 to 101. |
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Step (3) Perform a forward computation from 20 to 101. Both coordinates check. |
b. Arc-based method
Step (2) Set up and solve Equations D-6 through D-9.
Step (3) Use Equations D-10 and D-11 to compute the two intersection points
Step (4) Of the two, select the appropriate intersection point.
Point 101 is located southwest of the base line.
Point | North | East | From base line |
1011 | 5077.015 | 1363.991 | north east |
1012 | 4574.617 | 1085.956 | south west |
The correct intersection point is 1012: (4754.617 ft N, 1085.956 ft E), same as the triangle-based solution.